Răspuns:
3.
MP2O5=2x31+5x16=142g/mol
m=nxM=5x142=710g P2O5
MH3PO4=3x1+31+4x166=98g/mol
142g.........................2x98g
P2O5 + 3 H2O → 2 H3PO4
710g...........................xg
x=710x2x98/142=980g H3PO4
4.
125kgfier+250kgcurpu+25kg carbon+ 100kg siliciu=500kg aliaj
500kg aliaj.......125kg fier.........250kg cupru........25kg carbon.......100kg siliciu
100kg aliaj...........x%fier..............y%cupru...............z% carbon..............t% siliciu
x=100x125/500=25%Fe
y=250x100/500=50% Cu
z=25x100/500=5%C
t=100x100/500=20%Si
Explicație: