[tex]\it \Big[\Big(\dfrac{^{2)}7}{\ 3}-\dfrac{^{3)}3}{\ 2}\Big)^2-\Big(\dfrac{1}{2}\Big)^2\Big]\cdot\dfrac{12^2}{19}+1=\Big(\dfrac{25}{36}-\dfrac{^{9)}1}{\ \ 4}\Big)\cdot\dfrac{144}{19}+1=\dfrac{16}{36}\cdot\dfrac{144}{19}+1=\\ \\ \\ =\dfrac{64}{19}+1=3\dfrac{7}{19}+1=4\dfrac{7}{19}[/tex]
