[tex]\it \mathcal{V}_{cub}=4^3=64\ cm^3\\ \\ \mathcal{V}_{gum\breve a}=2\cdot1,5\cdot(1\dfrac{3}{9})=3\cdot\dfrac{12}{9}=\dfrac{36}{9}=4cm^3\\ \\ \\ \mathcal{V}_{ap\breve a} = 64-4=60\ cm^3\ \ \ \ \ (1)\\ \\ \mathcal{V}_{ap\breve a}=\mathcal{A}_{b}\cdot h=4^2\cdot h=16h\ \ \ \ \ (2)\\ \\ (1),\ (2) \Rightarrow 16h=60 \Rightarrow h=\dfrac{\ 60^{(4}}{16}=\dfrac{15}{4}=3,75\ cm[/tex]
