Răspuns:
Explicație:
a.
4moli CaO
masa de CO2
-se afla g CaO
MCaO= 40 + 16=56----> 56g/moli
m= 4moli . 56g/moli = 224g CaO
-se afla masa de O din CaO
56 g CaO-------16gO
224g ------------------x
x= 224 . 16 : 56= 64g O
-se afla masa de CO2 care contine 64 g O
M CO2= 12 + 2.16=44------> 44g/moli
44g CO2---------------32g O
yg CO2-----------------64gO
y= 44. 64 : 32= 88 g CO2
b.
3,4g NH3
molecule H2O
MNH3= 14 + 3=17----> 17g/moli
17g NH3------------3 g H
3,4g Nh3------------xgH
x= 3,4 . 3 : 17= 0,6 g H
MH2O= 2 + 16=18----> 18g/moli
18 g H2 O------------2g H
yg H2O-----------------0,6g H
y= 18 . 0,6 : 2= 5,4 gH2 O
n= 5,4g : 18g/moli = 0,3 moli H2O
1mol H2O--------------6,022.10²³ molecule H2O
0,3moli H2O----------------------z
z= 0,3 . 6,022.10²³= 1 , 8066 . 10²³molecule H2 O
c.
1,89g HNO3
moli H2SO4
M HNO3= 1 + 14 + 3.16= 63-----> 63g/moli
63g HNO3---------------48g O
1,89g HNO3----------------xg O
x= 1,89 . 48 : 63= 1,44 g O
M H2SO4= 2 + 32 + 4.16=98------> 98g/moli
98g H2 SO4------------------64g O
ygH2SO4-----------------------1,44gO
y= 98 . 1,44 : 64= 2,205 g H2SO4
n= 2,205g : 98g/moli=0,0225moli H2SO4
d.
640 g SO2
masa de SO3
MSO2= 32 + 2.16=64-----> 64g/moli
n= m : M
n= 640g : 64g/moli= 10 moli SO2
1mol SO2------------------------6,022.10²³molecule SO2
10 moli SO2---------------------------x
x= 10 . 6,022.10²³= 60, 22.10²³ moleculeSO2
MSO3= 32 + 3.16= 80-----> 80g/moli
1mol SO3-------------------6,022.10²³molecule SO3
zmoli SO3------------------------60,22.10²³ molecule SO3
z= 60,22.10²³ : 6,022.10²³ = 10 moli SO3
m= n .M
m= 10moli . 80g/moli= 800g SO3
e.
md= 25g CuSO4 . 5H2O
mapa= 75g
M=64 + 32 + 4.16 + 5.18= 160 + 90
mapa = 90 g
250g CuSO4 .5H2O-----------------90g H2O
25g--------------------------------------------a
a= 25 .90 : 250= 9g H2O
mapa total= 75 + 9= 84g
n = 84g : 18g/moli=4,66moli H2O
1mol H2O---------------6,022.10 ²³ molecule H2O
4,66moli H2O-------------------------x
x= 4,66 . 6,022.10²³= 28,06. .10²³molecule H2O