K+1→k+1
Mn+7..→.Mn+2 !!!!
O-2→O-2
H+1→.H+1
Cl-1→Cl2 0 !!!
Mn+7(trece in )+2(scrie +5e →) Reducere
2Cl-1(scrie-2e he sageata)Cl0 Oxidare
Agentul reducator:HCl
Agent oxidant:KMnO4
Amplificam prima reactie cu 2 far cealalta cu 5 ca sa egalezi electronii si he urma scri coeficienti
2KMnO4+16HCl→2KCl+2MnCl2+5Cl2+8H2O