[tex] [6-(4+ \frac{1}{ 2} )]:0,03=[/tex]
[tex] [6-( \frac{8}{2} + \frac{1}{ 2} )]:0,03=[/tex]
[tex](6- \frac{9}{ 2} ) \div \frac{3}{100} =[/tex]
[tex] ( \frac{12}{2} - \frac{9}{ 2} ) \div \frac{3}{100} =[/tex]
[tex] \frac{3}{2} \times \frac{100}{3} =[/tex]
[tex] = \frac{100}{2}[/tex]
[tex] = 50[/tex]
