Răspuns :
3[23+6x-4]<=0
3(19+6x)<=0
57+18x<=0
18x<=-57
x<=-57/18
x<=-3 1/6(minus 3 intregi si o sasime)
S=(- infinit;-3 1/6]
3(19+6x)<=0
57+18x<=0
18x<=-57
x<=-57/18
x<=-3 1/6(minus 3 intregi si o sasime)
S=(- infinit;-3 1/6]