Răspuns: [tex]\bf\red{\bf~ \dfrac{4}{5} ~}[/tex]
Explicație pas cu pas:
[tex]\bf [1,2+3,(3)]:5,(6)=\bigg(\dfrac{12}{10}+\dfrac{33-3}{9}\bigg): \dfrac{56-5}{9}=[/tex]
[tex]\bf \bigg(\dfrac{12^{(2}}{10}+\dfrac{30^{3}}{9}\bigg): \dfrac{51^{3}}{9}=\bigg(\dfrac{^{3)~}6}{5}+\dfrac{^{5)}10~}{3}\bigg): \dfrac{17}{3}=[/tex]
[tex]\bf \bigg(\dfrac{18}{15}+\dfrac{50}{15}\bigg)\cdot \dfrac{3}{17}=\dfrac{\not68}{\not 15}\cdot\dfrac{\not3}{\not17} =\red{\boxed{\bf~ \dfrac{4}{5} ~}}[/tex]
==pav38==
