Răspuns: [tex]\bf \pink{\bf~ \dfrac{41}{21}~}[/tex]
Explicație pas cu pas:
[tex]\bf \bigg(1\dfrac{4}{5}:2\dfrac{2}{5}-\dfrac{1}{\not6}\cdot \dfrac{\not2}{5}\bigg)\cdot \dfrac{6}{7}= \bigg(\dfrac{1\cdot5+4}{5}:\dfrac{2\cdot5+2}{5}-\dfrac{1}{3}\cdot \dfrac{1}{5}\bigg)\cdot \dfrac{2\cdot7+6}{7}=[/tex]
[tex]\bf \bigg(\dfrac{9}{5}:\dfrac{12}{5}-\dfrac{1}{15}\bigg)\cdot \dfrac{20}{7}= \bigg(\dfrac{\not9}{\not5}\cdot\dfrac{\not5}{\not12}-\dfrac{1}{15}\bigg)\cdot \dfrac{20}{7}=[/tex]
[tex]\bf \bigg(\dfrac{^{15)}3~}{4}-\dfrac{^{4)}1~}{15}\bigg)\cdot \dfrac{20}{7}=\dfrac{45-4}{60}\cdot \dfrac{20}{7}= \dfrac{41}{\not60}\cdot \dfrac{\not20}{7}=[/tex]
[tex]\bf \dfrac{41}{3}\cdot \dfrac{1}{7}=\pink{\boxed{\bf~ \dfrac{41}{21}~}}[/tex]
==pav38==
