Răspuns:
MCu3(PO3)2=3x64+3x31+6x16=381g/mol
n=m/M
m=nxM=3x381=1143g Cu3(PO3)2
MH2SO3=2x1+32+3x16=82g/mol
82gH2SO3..............48gO
xgH2SO3...................80gO
x=80x82/48=136,67gH2SO3
MSO3=32+3x16=80g/nol
80gSO3...............32gS..........48gO
100gSO3...............x%S...........y%O
x=100x32/80=calculeaza
y=100x48/80=calculeaza
(NH4)2CO3
raport de masa N:H:C:O=28:8:12:48=7:2:3:12
Explicație:
