Răspuns:
[tex]25)1.1(3) \div (0.5 + 0.(3) + 0.1(6)) = \\ = \frac{113 - 11}{90} \div ( \frac{5}{10} + \frac{3}{9} + \frac{16 - 1 }{90} ) = \\ = \frac{102}{90} \div ( \frac{45}{90} + \frac{30}{90} + \frac{15}{90} ) = \frac{102}{90} \div \frac{90}{90} = \frac{102}{90} \div 1 = \frac{102}{90} = \frac{34}{30} = \frac{17}{15} [/tex]
[tex]26)5.2 - 0.(3) \div (0.5 - 0.(6) \div 3)) = \\ = \frac{52}{10} - \frac{3}{9} \div ( \frac{5}{10} - \frac{6}{9} \div \frac{3}{1} ) \\ \frac{52}{10} - \frac{3}{9} \div ( \frac{5}{10} - \frac{6}{9} \times \frac{1}{3} ) = \\ = \frac{52}{10} - \frac{3}{9} \div ( \frac{5}{10} - \frac{6}{27} ) = \\ = \frac{52}{10} - \frac{ 3}{9} \div ( \frac{5}{10} - \frac{2}{9} ) = \\ = \frac{52}{10} - \frac{3}{9} \div ( \frac{45}{90} - \frac{20}{90} ) = \\ = \frac{52}{10} - \frac{3}{9} \div \frac{25}{90} = \\ = \frac{52}{10} - \frac{3}{9} \times \frac{90}{25} = \\ = \frac{52}{10} - \frac{3}{1} \times \frac{10}{25} = \frac{52}{10} - \frac{30}{25} = \frac{26}{5} - \frac{6}{5} = \frac{20}{5} = 4[/tex]
