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a fost răspuns

(x+3)^2=(3x-1)*(9-x)

Răspuns :

x^2+6x+9=-3x^2+28x-9
4x^2-22x+18=0
2x^2-11x+9=0
Δ=121-72=49
x1=(11-7)/4=1
x2=(11+7)/4=9/2
x^2+6x+9=27x-3x^2-9+x
4x^2-22x+18=0
delta=22*22-4*4*18=196
x1=(22+14)/8=4,5
x2=1

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