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Dontworry
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1.96g de amestec echimolecular de propena si 2-butena se oxideaza cu o solutie KMnO4, 0.1M, in mediu de H2SO4. substanta organica obtinuta este dizolvata in 100g apa. Se cere:
a) calculeaza volumul de solutie KMnO4 folosit
b) calculeaza concentratia procentuala a solutiei de substanta organica obt. in final
c) scrie 2 utilizari practice ale substantei oraganice obtinute in urma oxidarii

Răspuns :

Mirceavaman
Raportul molar: x:x => 42x+56x=96x=96 => x=1mol
1mol................5moli.....60g............................18g
CH2=CH-CH3 + 5[O] -> CH3-COOH + CO2 + H2O
1mol..............a=5moli..b=60g.........................f=18g
1mol......................4moli.....2*60g
CH3-CH=CH-CH3 + 4[O] -> 2CH3-COOH
1mol.....................c=4moli..d=120g
2moli...........................5moli
2KMnO4 + 3H2SO4 -> 5[O] + K2SO4 + MnSO4 + 3H2O
e=3,6moli....................9moli
Vs=n/Cm=3,6/0,1=36L KMnO4
mCH3-COOH=180g=md
ms=md+100=180+100+18=298g solutie
c=md*100/ms=180*100/298=60,4%
industria alimentara, ca si otet