Explicație pas cu pas:
[tex]\int {(x + 2018)}^{2} dx[/tex]
[tex]u = x + 2018 = > du = 1dx[/tex]
[tex]\int {(u)}^{n} du = \frac{ {u}^{n + 1} }{n + 1} = > \int {(u)}^{2} du = \frac{ {u}^{3} }{3} [/tex]
=>
[tex] \int {(x + 2018)}^{2} dx = \frac{ {(x + 2018)}^{3} }{3} + c [/tex]
