n- primul numar
n+1-al doilea
n+2-al treilea
n+3-al patrulea
n+4-al cincilea
a) consideram n=2
=>sirul va fi 2,3,4,5,6
(3+4+5+6)-(2+3+4+5)
18-14
4
consideram n=30
=>sirul va ti 30,31,32,33,34
(31+32+33+34)-(30+31+32+33)
130-126
4
b)n+n+1+n+2+n+3+n+4=130
5n+10=130
5n=130-10
5n=120
n=120:5
n=24=>n+1=25
n+2=26
n+3=27
n+4=28