Răspuns :
[tex]a+b=(a-b)+24 \\ a+b=4(a-b) \\ 4(a-b)-(a-b)=24 \\ 3(a-b)=24 \\ a-b=24:3 \\ a-b=8 \\ a+b=8+24 \\ a+b=32 \\ a+b+a-b=32+8 \\ 2a=40 \\ a=40:2=20 \\ b=32-20=12[/tex]
24;3=8 diferenta 8'4=32 suma 32-8=24 doua parti 24;2=12 primul numar 12+8=20 al doilea numar