Răspuns:
a > b
Explicație pas cu pas:
[tex]a = \frac{1}{ \sqrt{2} } \: si \: b = \frac{1}{ \sqrt{3} } [/tex]
[tex]a = \frac{1}{ \sqrt{2} } = \frac{ \sqrt{3} }{ \sqrt{2} \times \sqrt{3} } = \frac{ \sqrt{3} }{ \sqrt{6} } \\ b = \frac{1}{ \sqrt{3} } = \frac{ \sqrt{2} }{ \sqrt{3} \times \sqrt{2} } = \frac{ \sqrt{2} }{ \sqrt{6} } [/tex]
[tex] \frac{ \sqrt{3} }{ \sqrt{6} } > \frac{ \sqrt{2} }{ \sqrt{6} }[/tex]
[tex] = > a > b[/tex]
