Folosim formula a²+b²=a²+2ab+b² , unde
a=[tex] \sqrt{5-2 \sqrt{6} } [/tex]
b=[tex] \sqrt{5+2 \sqrt{6} } [/tex]
a²=[tex]5-2 \sqrt{6} [/tex]+2[tex] \sqrt{(5-2 \sqrt{6)}(5+2 \sqrt{6} )} } [/tex]+[tex]5+2 \sqrt{6} [/tex]
Folosind formula a²-b²=(a-b)(a+b) relatia devine
a²=10+2[tex] \sqrt{25-24} [/tex]
a²=10+2
a=12
