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Rainzios457
a fost răspuns

Rezolva in Q ecuatia:
[tex] \frac{3}{10} + \frac{3x - 2}{4} = 1 \frac{3}{10} - \frac{2x - 4}{5} [/tex]


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Explicație pas cu pas:

Vezi imaginea Dariusbarbu

[tex]\it \dfrac{3}{10}+\dfrac{3x-2}{4}=1\dfrac{3}{10}-\dfrac{2x-4}{5} \Rightarrow \dfrac{3x-2}{4}+\dfrac{2x-4}{5}=1\dfrac{3}{10}-\dfrac{3}{10} \Rightarrow\\ \\ \\ \Rightarrow \dfrac{^{5)}3x-2}{4}+\dfrac{^{4)}2x-4}{5}=1 \Rightarrow \dfrac{15x-10+8x-16}{20}=1 \Rightarrow 23x-26=20\Rightarrow\\ \\ \\ \Rightarrow 23x=20+26 \Rightarrow 23x=46\Big|_{:23} \Rightarrow x=2[/tex]