triunghiurile AOB si DOC sunt isoscele
in triunghiul BOM
MB=√50²-30²=√2500-900=√1600=40
AB=40x2=80
in triunghiul COM -N
NC=√50²-40²=√2500-1600=√900=30
DC=30x2=60
ABCD este un trapez
ducem DE_I_AB
AE=(80-60)/2=10
DE=MN=30+40=70
AD=BC=√70²+10²=√4900-100=√5000=50√2
P=60+80+2x50√2=140+100√2
A=(80+60)x70/2=140x70/2=4900 cm²
2.HB=√26²-24²=√676-576=√100=10
PH=√40²-24²=√1600-576=√1024=32
PB=10+32=42
PA=√40²-26²=√1600-676=√924=2√231
P=42+2√231+26+26=94+2√231
A ΔPBO=42x24/2=504 cm²
A ΔPAO=2√231x26/2=26√231 cm²
Atotala=504+26√231
3
m(<NOM)=120⁰ ⇒m(<OMN)=m(<ONM)=(180⁰-120⁰)/2=30⁰
m(<NOP)=40⁰ ⇒m(<ONP)=m(<OPN)=(180⁰-40⁰)/2=70⁰
m(<POQ)=130⁰ ⇒m(<OPQ)=m(<OQP)=(180⁰-130⁰)/2=25⁰
m(<QOM)=70⁰ ⇒m(<OQM)=m(<OMQ)=(180⁰-70⁰)/2=55⁰
m(<MNP)=30⁰+70⁰=100⁰
m(<NPQ)=70⁰+25⁰=95⁰
m(<PQM)=25⁰+55⁰=80⁰
m(<QMN)=55⁰+30⁰=85⁰
4.
masurile arcelor :
BD =m(<BAD) x2=30⁰x2=60⁰
CD =m(<DAC) x2=30⁰x2=60⁰
CE =m(<CBE) x2=25⁰x2=50⁰
AE =m(<EBA) x2=25⁰x2=50⁰
BF=m(<BCF) x2=35⁰x2=70⁰
AF=m(<ACF) x2=35⁰x2=70⁰
