Răspuns:
b) 2014
Explicație pas cu pas:
b)
[tex]a = {2}^{2018} + 15 \times {2}^{2014} + {2}^{2012} + {2}^{3} + {2}^{2} + 2 = {2}^{2012} \times ( {2}^{4} + 15 \times {2}^{2} + 1) + 14 =125 \times {2}^{2012} + 14 = 125 \times {2}^{4} \times {2}^{2008} + 14 = 2000 \times {2}^{502 \times 4} + 14 [/tex]
ultimele 4 cifre ale sumei: 2014
