[tex]\it a)\ \ =\dfrac{7+4}{3}=\dfrac{11}{3}\\ \\ \\ b)\ \ =\dfrac{3+8}{7}=\dfrac{11}{7}\\ \\ \\ c)\ \ =\dfrac{7-3}{5}=\dfrac{4}{5}\\ \\ \\ d)\ \ =\dfrac{-13+5}{6}=\dfrac{-8^{(2}}{6}=-\dfrac{4}{3}\\ \\ \\ e)\ \ =\dfrac{-7-3}{4}=\dfrac{-10^{(2}}{4}=-\dfrac{5}{2}[/tex]
