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a fost răspuns

rezolvati in multimea z inecuatia :
[tex]1-2* \frac{2x+1}{x-3} + ( \frac{2x+1}{x-3})[/tex]²>0

Răspuns :

Notam: 
[tex] \frac{2x+1}{x-3}=t \\ Obtinem \\ 1-2t+t^2\ \textgreater \ 0 \\ sau \\ t^2-2t+1\ \textgreater \ 0 \\ t^2-2t+1=0 \\ \Delta=4-4=0 \\ t_{1}=t_2= \frac{2}{2}=1 \\ \frac{2x+1}{x-3}=1 \\ 2x+1=x-3 \\ 2x-x=-3-1 \\ x=-4 \\ [/tex]

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