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a fost răspuns

Cate grame se gasesc in :
4 moli de Kcl
2,5 moli Zn(No2)2

Răspuns :

Nalaby
m= M(KCl) * 4 moli= (39 + 35.5)g/moli *4=74.5*4=298 g
m(Zn(NO2)2)= M(Zn(NO2)2) * 2.5 moli=(65 + 14*2 + 16*2) g/moli *2.5 moli=125*2.5=312.5 g
m(HCl)=(1+35.5)*3=36.5*3=109.5 g
m(Mg(NO3)2)=(24+14*2+16*3*2)*1.5=148*1.5=222g

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