Răspuns:
2x{3x3x11:[2x2+(1x3- x)X2+1]}-18=0
2x{9x11:[4+(3- x)X2+1]}-18=0
2x{99:[4+(3- x)X2+1]}=0+18=18
{99:[4+(3-x)X2+1]}=18:2
99:[4+(3-x) X2+1]=9
[4+(3-x)X2+1]=99:9
4+(3-x)X2+1=11
4+(3-x)X2=11-1=10
(3-x)X2=10-4=6
(3-x)=6:2
3-x=3
x=3-3
x=0
