460 g .................................. 100%
m.pur .................................. 80%
= 368 g
368 g m g
CH3O-C6H4-COOH + H2O <==> HO-C6H4-COOH + CH3OH
152 138
=> m= 368x138/152 = 334,10 g acid salicilic la 100%
334,10 g ............................... 100%
Cp ....................................... 90%
= 300,7 g
