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Alinabubulina3
a fost răspuns

1. In cati moli de H2SO4 se afla aceeasi cantitate de sulf ca in 128 kg de SO2?
2. In cati litri de amoniac se afla acelasi numar de molecule ca in 4 kg de H2?
3.Cate g de Fe se afla in 4 moli de substanta ce prezinta raportul de masa: Fe:S:O=7:4:8
4.Calculati continutul procentual de oxigen din 10 moli de FeSO4 x 7H2O
5.Baza unui metal divalent contine 54,05% metal.Determinati formula bazei
heeelp

Răspuns :

Daria85
128kg=128000g
Masa SO2=A Sulf+ 2*A Oxigen=32+32=64g
64g SO2.......................32g S
128000g SO2.................ag S
a=32*128000/64=128000/2=64000g S
Masa H2SO4=2*A Hidrogen+A Sulf+4*A Oxigen=2+32+64=98g
98g H2SO4....................32g S
bg..................................64000g S
b=98*64000/32=98*2000=196000g H2SO4
Numarul de moli=196000/98=2000 moli H2SO4

Fe→7:56=1/8=0,125
S→4:32=1/8=0,125
O→8:16=1/2=0,5
Se imparte tot la cea mai mica valoare si ai
Fe→0,125:0,125=1
S→0,125:0,125=1
O→0,5:0,125=4 deci FeSO4
M FeSO4=A Fier+A Sulf+4*A Oxigen=56+32+48=136g
1 mol FeSO4................136g..................56g Fe
4 moli FeSO4.........................................xg Fe
x=4*56=224g Fe

4kg=4000g=2000 moli
22,4*2000=44800 L NH3

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