Răspuns:
Explicație pas cu pas:
trasam BE⊥CD; AD=BE=2√2
ΔBEC = drept. ;CE²= BC²=BE²=(2√6)² -( 2√2)²=24-8 =16
CE==√16 =4 cm
ΔCBD drept, BC²=CE*CD
(2√6) =4*CD
24 =4*CD
CD=24/4 =6cm ; ⇒DE=AB=6-4 =2 cm
ΔDAB ⇒BD²=AD²+AB²=(2√2)²+2²=8+4 =12 cm
BD =√12=2√3 cm
ΔADC = drept, AC²=AD²+CD²=(2√2)²+6²=8+36 =44
AC=√44 =2√11 cm
AF⊥BD ⇒AF=C*C/ip =(2*2√2) /2√3=2√6/3 cm