Toate muchiile sunt congruente
Notam cu a=muchia
AD=a
AB=a
[tex]AM=\frac{a}{2}[/tex]
ΔDAM dr in A, aplicam Pitagora
DM²=AD²+AM²
[tex]DM^2=a^2+\frac{a^2}{4} =\frac{5a^2}{2} \\\\DM=\frac{a\sqrt{5} }{2}[/tex]
∡((DCM),(ABC))=∡((DMC),(AMC))=∡DMA
AM⊥CM
[tex]tgDMA=\frac{DA}{AM} =\frac{a}{\frac{a}{2} }=2[/tex]
tg∡DMA=2
