Răspuns:
Explicație pas cu pas:
log(x+1 ;2x^3 +2x^2 -3x +1) = log(x+1; (x+1)^3)
2x^3 +2x^2 -3x +1 = (x+1)^3 = (x+1)(x^2+2x +1)
2x^3 +2x^2 -3x +1 = x^3 +2x^2 +x +x^2+2x +1
2x^3 +2x^2 -3x +1 = x^3 +3x^2 +3x +1
x^3 -x^2 -6x = 0
x(x^2 -x -6) = 0
x1 = 0, nu convie, x+1 = 0+1 = 1, baza sa fie ≠ 1
x^2 -x -6 = 0, delta = 1 +24 = 25
x2,3 = (1 -+5)/2
x2 = -4/2 = -2, nu e buna, val.de sub log e < 0
x3 = 6/2 = 3, convine
