Răspuns:
x_____196 g
KOH + H2SO4 ==> K2SO4 + H2O
56g___98g
[tex]c = \frac{md \times 100}{ms} = > \\ \\ md = \frac{c \times ms}{100} = \\ \\ = \frac{196 \times 49}{100} = \\ \\ = 96.04 \: g[/tex]
M KOH = A K + A O + A H =
= 39 + 16 + 1
= 56 g pe mol
M H2SO4= 2×A H + A S + 4×A O
= 2×1 + 32 + 4×16
= 98 g pe mol
[tex]x = \frac{56 \times 196}{98} = \\ \\ = 112g[/tex]
[tex]c = \frac{md \times 100}{ms} = > \\ \\ ms = \frac{md \times 100}{c} = \\ \\ = \frac{112 \times 100}{49} = \\ \\ = 228.57g[/tex]
Succes!
