a) -1 + 1 < 1 => 0< 1 A ( adevărat )
b)3 x -1 >_ -3 => -3 = -3 A
c)-4 x -1 > 8 => 4 > 8 F ( fals )
d) 5 -(-1) <_ 8 => 5 + 1 ( pt. că avem - ori - ) <_ 8 => 6 < 8 A
e) 10 : (-(-1)) > 5 => 10 : 1 > 5 => 10 > 5 A
f)7 x -1 <_ -1 -6 => -7 = -7 A
g)2(-1+1) <0 => 2 x 0 < 0 => 0 < 0 F
h) 3 x -1 : (-3) >_ 1 => -3 : -3 >_ 1 => 1 = 1 A
