a) AN=?
AM=MC=4
->tr AMN este asemanator cu tr ABC
deci-> AN/AC = AM/AB = MN/BC
-> AN/8 = 4/12 = MN/9
AN/8 = 4/12 => AN= 8•4/12 = 8/3 = 2,6
AN=2,6 cm
b) MN=?
MN/9 = 4/12 => MN= 9•4/12 = 3
MN=3 cm
c) Perimetrul tr AMN=?
P= AN + MN + AM= 4+3+8/3
= 12+9+8 /3 = 29/3 = 9,6
P=9,6 cm
