a.
Capacitate totala 20l,
Observam ca sunt 5 "bucati"
Fiecare bucata are 20:5=4 l apa
b.
[tex]\frac{20}{20} \ sau\ \frac{5}{5}[/tex]
c.
Deci avem umplut: 4×3=12 l apa
d.
[tex]\frac{3}{5}[/tex]
3 bucati umplute, 5 total
e.
[tex]\frac{2}{5}[/tex]
2 goale, 5 total
f.
[tex]\frac{3}{5} > \frac{2}{5}[/tex]
Avand acelasi numitor 5, comparam 3 cu 2
3>2
Am atasat exercitiul cu cerinta completa