Vs = 4000 mL = 4 L
md = 1,6 g NaOH, M.NaOH = 23+1+16 = 40 g/mol
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pH = ?
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Cm = md/MxVs = 1,6/40x4 = 10⁻² mol/L (M)
NaOH = baza tare , va disocia complet in solutie apoasa
pOH = -lg[HO⁻] = -lg(10⁻²) = -(-2) = 2
pH + pOH = 14 => pH = 14 - pOH = 14 - 2 = 12
