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Descompuneti in factori:
16(3x+2)^2-9(x+1)^2
Rezolvarea completa!

Răspuns :

Simonarusu
=[4(3x+2)]²-[3(x+1)]²=[4(3x+2)-3(x+1)][4(3x+2)+3(x+1)]=                                         =(12x+8-3x-3)(12x+8+3x+3)  =(9x+5)(15x+11)
[tex]16(3x+2)^2-9(x+1)^2=[4(3x+2)-3(x+1)][4(3x+2)+3(x+1)] \\ = [12x+8-3x-3][12x+8+3x+3]=(9x+5)(15x+11)[/tex]

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