x²-3x+1=0
a=1
b=-3
c=1
Δ=b²-4ac (4ac, adica 4·a·c)
Δ=(-3)²-4·1·1
Δ=9-4
Δ=5
5>0
[tex] x_{1,2}= \frac{-b+sau- \sqrt{delta} }{2a} [/tex]
[tex] x_{1} = \frac{-(-3)+ \sqrt{5} }{2} \\ x_{1}= \frac{3+ \sqrt{5} }{2} [/tex]
[tex] x_{2} = \frac{-(-3)- \sqrt{5} }{2} \\ x_{2} = \frac{3- \sqrt{5} }{2}. [/tex]
Solutiile ecuatiei sunt [tex] (\frac{3+ \sqrt{5} }{2} ; \frac{3- \sqrt{5} }{2}).[/tex]
Sper ca te-am ajutat! :)
