Răspuns:
Explicație pas cu pas:
Δ DESF- DE=DF
DA- mediana
EB- mediana
AE=5cm
BD= 6 cm
.............................
PΔDEF=?
...............................
PΔDEF= DE+EF+DF
DF= 5*2=10cm
DE= 6*2=12c
DF=DE=12cm
P= 12+12+10= 34 cm
-
3)
ΔABC- AB=BC=AC
AM- mediana
MB= 8cm
......................................
PΔABC= ?
....................................
-
BC= MB*2
BC= 8*2
BC= 16 cm
AB=AC=BC= 16 cm
PΔABC= AB+BC+AC
PΔABC= 16+16+16
PΔABC=48 cm
