[tex]\it 0,0(2)=\dfrac{\ 2^{(2}}{90}=\dfrac{1}{45};\ \ \ 0,125=\dfrac{\ 125^{(125}}{1000}=\dfrac{1}{8}\\ \\ \\ \{a,\ b\}\ i.\ p.\ \Big\{\dfrac{1}{45},\ \dfrac{1}{8}\Big\}\Rightarrow \{a,\ b\}\ d.\ p.\ \{45,\ 8\} \Rightarrow a=45k,\ \ b=8k\\ \\ \\ a:b=4\ \ rest\ 39 \Rightarrow a=4b+39 \Rightarrow 45k=32k+39|_{-32k} \Rightarrow 13k=39 \Rightarrow k=3\\ \\ a=45\cdot3=135;\ \ b =8\cdot3=24[/tex]
