Răspuns:
Explicație:
200 kg NaCl , p=80%
se descomp.
a. masa de imp.
b. masa de Na
nr. moli Cl2
mp= p . mi : 100
mp= 200 . 80 : 100 =160kg NaCl
m impuritati = 200kg - 160kg = 40kg
160kg xkg ykg
2NaCl = 2Na + Cl2
2.58,5kg 2.23kg 71kg
x= 160 .46 : 117 =62,9 kg Na
y= 160 .71 : 117=97,09 kg Cl
n= m : M
n= 97,09kg : 71kg/kmoli= 1,367 kmoli CL2 = 1367 moli Cl2
M NaCl= 23 + 35,5= 58,5----> 58,5kg/kmoli
MCl2= 2 . 35,5 = 71-----> 71kg/kmoli