Vom nota cu x numarul de jeleuri si vom avea
[tex]\frac{x}{2}[/tex] in prima zi
[tex]\frac{1}{3} (x-\frac{x}{2} )=\frac{x}{6}[/tex] a doua zi
[tex](x-\frac{x}{2} -\frac{x}{6}):2=\frac{2x}{6} \times\frac{1}{2} =\frac{x}{6}[/tex] a treia zi
[tex]x-\frac{x}{2} -\frac{x}{6} -\frac{x}{6} =7\\\\\frac{x}{2} -\frac{2x}{6} =7\\\\3x-2x=42\\x=42[/tex]