Răspuns:
MNa=23g/mol
n=m/M=4,6/23=0,2moli Na
2moli........................................1mol
2Na + 2H2O → 2NaOH + H2↑
0,2moli.........................................xmoli
x=0,2x1/2=0,1moli H2
calculam in grame
MNaOH=23+16+1=40g/mol
2x23g.......................2x40g
2Na + 2H2O → 2NaOH + H2↑
4,6g............................yg
y=4,6x2x40/2x23=8g NaOH
Explicație:
