Răspuns :
[tex]\it I)\ cite\d ste\ \dfrac{1}{4}p;\ \ mai\ r\breve am\hat a n\ \ \dfrac{3}{4}p\\ \\ \\ II)\ cite\d ste\ \dfrac{1}{2}\cdot\dfrac{3}{4}p=\dfrac{3}{8};\ \ mai\ r\breve am\hat a n\ \ \dfrac{3}{8}p\\ \\ \\ III)\ cite\d ste\ \dfrac{1}{2}\cdot\dfrac{3}{8}p=\dfrac{3}{16};\ \ mai\ r\breve am\hat a n\ \ \dfrac{3}{16}p\\ \\ \\ IV)\ cite\d ste\ \ \dfrac{3}{16}p=48 \Rightarrow p=\not48\ ^{16}\cdot\dfrac{16}{\not3}=16\cdot16=256[/tex]