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Opisicamica3
a fost răspuns

calculeaza:
a)50:(3x3-3:3-3x3:3)=b)(5x8+14:7):(3x3-14:7)=c)2x3x5+60:10:6-31=d)16-16:8+(16-16):8=99=
e)(100-6--6x5)x5+(10-6:3):8=f)45:5+(54+45):(4+5)=
help me please

Răspuns :

a)50:(3x3-3:3-3x3:3)=50;(9-1-3)=50:5=10
b)(5x8+14:7):(3x3-14:7)=(40+2):(9-2)=42;7=6
c)2x3x5+60:10:6-31=30+1-31=0
d)16-16:8+(16-16):8=99=16-2+0=14
e)(100-6--6x5)x5+(10-6:3):8=64x5+8:8=320+1=321
f)45:5+(54+45):(4+5)=9+99:9=9+11=20
A) 50:(3×3-3:3-3×3:3)=50:(9-3:3-9:3)=50:(9-1-3)=50:8-3=50:5=10