Răspuns:
a)
[tex] {2}^{29} + {2}^{40} \div {2}^{11} = {2}^{29} + {2}^{40 - 11} = {2}^{29} + {2}^{29} = 1 \times {2}^{29} + 1 \times {2}^{29} = (1 + 1) + \times {2}^{29} = 2 \times {2}^{29} = {2}^{1} \times {2}^{29} = {2}^{1 + 29} = {2}^{30} [/tex]
b)
[tex] {12}^{20} \div {2}^{40} = \frac{ {12}^{20} }{ {2}^{40} } = \frac{ {6 \times 2}^{20} }{ {2}^{40} } = \frac{ {6}^{20} \times {2}^{20} }{ {2}^{40} } = \frac{ {6}^{20} }{ {2}^{40 - 20} } = \frac{ {6}^{20} }{ {2}^{20} } = \frac{ ({3 \times 2)}^{20} }{ {2}^{20} } = \frac{ {3}^{20} \times {2}^{20} }{ {2}^{20} } = {3}^{20} [/tex]
a<b
Sper că te-am ajutat
