Răspuns:
Explicație pas cu pas:
a.
[tex]\frac{7}{a+1} >\frac{5}{8}[/tex]
56>5a+5
5a<51
a<[tex]\frac{51}{5}[/tex]
a={10,9,8,7,...,0}
b.
[tex]\frac{6}{a-3} <\frac{12}{4}[/tex]
24<12(a-3) |:12
2<a-3
a>5
a={6,7,8...}
c.
[tex]\frac{a+3}{a+6} <\frac{2}{3}[/tex]
3a+9<2a+12
a<3
a={0,1,2}
d.
[tex]\frac{a+2}{a+3} >\frac{5}{9}[/tex]
9a+18>5a+15
4a>-3
a>[tex]-\frac{3}{4}[/tex]
a={0,1,2,...}
