a) A+B+C=912
A=B+234
C=B+378
B+234+B+B+274=912; 3xB=300; B=100
A=100+234=334; C=100+378=478
b) M+N+S=99
N=M+17
S=M+17+5=M+22
M+M+17+M+22=99; 3xM=60; M=20
N=20+17=37; S=20+22=42
c)D+F+G=912
F=D+2
G=D+4
D+D+2+D+4=912; 3xD=906; D=302
F=302+2=304; G=302+4=306
d)D+N+R=3705
N=D+350
R=D+355
D+D+350+D+355=3705; 3xD=3000; D=1000
N=1000+350=1350; R=1000+355=1355
Sper ca asa se rezolva exercitiul :)
