AJUTOOOOOR!!!!!! AM NEVOIE DE EA FACUT-A PANA LA 11
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Răspuns:
Explicație pas cu pas:
a. f(x)=x-4
∩OX, y=0⇒ x-4=0⇒x=4 A(4,0)
∩OY, x=0⇒ y=-4 B(0,-4)
b. ai atasat poza cu desenul
c. ΔAOB dreptunghic isoscel pentru ca AO=OB=4
[tex]A_{AOB}=\frac{AO\cdot OB}{2}=8[/tex]
d. tg ∡(Ox,AB)=tg ∡BAO=tg 45°=1
e. tg ∡(Oy,AB)= tg∡OBA=tg45°=1
f. MN⊥AB
In ΔMOA aplicam Pitagora
MA²=MO²+OA²
MA²=9+16=25
MA=5
In ΔAOB aplicam Pitagora
AB²=AO²+OB²
AB²=16+16=32
AB=4√2
MB=3+4=7
[tex]A_{MAB} =\frac{AO\cdot MB}{2} =\frac{MN\cdot AB}{2}[/tex]
[tex]\frac{4\cdot7}{2} =\frac{MN\cdot4\sqrt{2} }{2}[/tex]
[tex]MN=\frac{7\sqrt{2} }{2}[/tex]
g. Fie QP⊥AB
QO=3
[tex]A_{QBA}=\frac{BO\cdot QA}{2}=\frac{QP\cdot BA}{2}[/tex]
[tex]\frac{4\cdot7}{2} =\frac{QP\cdot 4\sqrt{2} }{2}[/tex]
[tex]QP=\frac{7\sqrt{2} }{2}[/tex]