ab+2b-3a-6=10
Dam factor comun
b(a+2)-3(a+2)=10
(a+2)(b-3)=10
Caz 1
a+2=2 b-3=5
a=0 b=8
Caz 2
a+2=-2 b-3=-5 b=-2
a=-4
Caz 3 a+2=5 a=3
b-3=2 b=5
Caz 4 a+2=-5 a=-7
b-3=-2 b=1
Caz 5 a+2=1 a=-1
b-3=10 b=13
Caz 6
a+2=-1 a=-3
b-3=-10 b=-7
Caz 7
a+2=10 a=8
b-3=1 b=4
Caz 8
a+2=-10 a=-12
b-3=-1 b=2
Sa mai verifici odată calculele te rog
