Răspuns:
[tex] \bf 4x^3(2x+1)-4x^2(2x+1)+2x^2-x = [/tex]
[tex] \bf (2x+1) \cdot(4x^3-4x^2)+2x^2-x = [/tex]
[tex] \bf (2x+1) \cdot4x^{2} \cdot( x-1)+2x \cdot(x - 1) = [/tex]
[tex]\bf (x - 1) \cdot[4x^{2} \cdot( 2x + 1)+2x ] =[/tex]
[tex]\bf (x - 1) \cdot2x \cdot[2x\cdot( 2x + 1)+1 ] =[/tex]
[tex] \red{ \boxed{\bf \: (x - 1) \cdot2x \cdot( 4x^{2} + 2x + 1 )} \: }[/tex]
==pav38==